The specific conductivity of a saturated solu | vedclass

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Question

(A) The molar conductivity at infinite dilution for $AgCl$ is given by Kohlrausch's law:$\Lambda_{m}^{\infty}(AgCl) = \lambda^{\infty}(Ag^+) + \lambda

Vedclass · Accepted Answer

$1.428 	imes 10^{-5} \, M$

Vedclass · Answer

(A) The molar conductivity at infinite dilution for $AgCl$ is given by Kohlrausch's law:$\Lambda_{m}^{\infty}(AgCl) = \lambda^{\infty}(Ag^+) + \lambda^{\infty}(Cl^-) = 60 + 80 = 140 \, S \, cm^2 \, mol^{-1}$.For a sparingly soluble salt,the solubility $S$ is related to specific conductivity $(K)$ and molar conductivity at infinite dilution $(\Lambda_{m}^{\infty})$ by the formula:$S = \frac{K 	imes 1000}{\Lambda_{m}^{\infty}(AgCl)}$.Substituting the given values:$S = \frac{2 	imes 10^{-6} 	imes 1000}{140} = \frac{2 	imes 10^{-3}}{140} \approx 1.428 	imes 10^{-5} \, M$.

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